In my math class we were shown this video that introduces the Monty Hall problem. Monty Hall hosted a game show named Let's Make a Deal in 1963, and one of the big games in this show was having a contestant pick a door out of the three shown. The objective of the game was to get the car. Mathematically there is a higher chance to pick the non-car since the probability would be about 66 percent. Then Monty would show one of the doors that was a non-car. Therefore, there is a 50 percent chance of getting the car right? Wrong! So what should you do? Stay with the picked door? Or swap your door?
Try it out by clinking here and see what happens after doing this experiment nine times.
So what was your result? You should have noticed that when you switched the door you would most likely get the car and if you stayed with your door, you would end up with a goat. Why? Well no matter what, the door with the non-car will be shown. There is a less chance of picking the car first so if you swap doors you have a 66 percent of getting a car instead of staying, which if you do stay, it will make you have a 33 percent chance of getting a car. Therefore if you swap, the higher probability you will have to win the car. Now that you know, don't you want to participate in the current Let's Make a Deal?
I thought your blog was amazing. It was very interesting and fun to read. I liked the video in this post because it went over exactly what we had talked about in class. Good job on your blog!
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